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It had nothing to do with the floating point approximation of things. I don't think I said that anywhere. It had more to do with the syntactic transformation wh
by reikonomusha 13y ago
It had nothing to do with the floating point approximation of things. I don't think I said that anywhere. It had more to do with the syntactic transformation while remaining precisely the same.
- mooism2 13y agoThe actual translation of the equation is > (1+ (exp (complex 0 pi))) #C(0.0d0 0.0d0) But you got > (1+ (exp (complex 0 pi))) #C(0.0d0 1.2246467991473532d-16) Which is not “precisely the same”. Hence my confusion.