4 ms·
It's not an appeal to authority. It's Bayesian probability. P(author_doing_fp_wrong) < P(author_doing_fp_wrong | author_invented_erlang)
by jasonwocky 13y ago
It's not an appeal to authority. It's Bayesian probability.
P(author_doing_fp_wrong) < P(author_doing_fp_wrong | author_invented_erlang)
- chc 13y agoNot sure if you got your sign backwards or if this is a really nerdy burn on Erlang.
- jasonwocky 13y agodamn! sign backwards! /blush
- abraininavat 13y agoEven with your operator fixed, this is still bull. This only only instructive if you have zero external knowledge regarding the context. Since we can read Joe Armstrong's words, and since we can read arianvanp's objection, and since most of us have brains, we can and should do a lot better than "bayesian probability".