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Of course that is the definition of a Harvard architecture. It doesn't says that it won't link, just that it won't work. If compiling to an architecture with sm
by poizan42 13y ago
Of course that is the definition of a Harvard architecture. It doesn't says that it won't link, just that it won't work. If compiling to an architecture with smaller sized code pointers than data pointers then the linker will most likely refuse to link it at all - otherwise it will have to truncate the adresses.