3 ms·
Correct, I can't see the practical use of this. If Alice and Bob must have a secure method to jointly compute K(A) ⊕ K(B), then why wouldn't then use that same
by _red 13y ago
Correct, I can't see the practical use of this.
If Alice and Bob must have a secure method to jointly compute K(A) ⊕ K(B), then why wouldn't then use that same method to just exchange the data?
- dsr_ 13y agoAt the time of their key-exchange meeting, they don't know what messages they will want to exchange later.