3 ms·
Just curious: how do the regexes compare when you use "^@(.*)@$" ? Semantically, it's closer to the string version. Realistically, you'd expect them to behave
by rcfox 13y ago
Just curious: how do the regexes compare when you use "^@(.*)@$" ? Semantically, it's closer to the string version.
Realistically, you'd expect them to behave exactly the same, but Go's pretty new, and you never know what is or isn't going to be optimized.
- Titanous 13y ago`\A@(.*)@\z` BenchmarkRegexp 500000 5181 ns/op BenchmarkStrings 10000000 171 ns/op