5 ms·

It's the http://www.arcadebliss.com/game/russian-roulette.htm http://www.arcadebliss.com/game/russian-roulette.htm of its decade...

• StavrosK 13y ago
  Why would someone not spin the revolver?
  • paulnechifor 13y ago
    Hardcore mode.
  • leddt 13y ago
    From what I can see, the opponent never spins. So I guess if you survive without spinning, they are more likely to lose on the next attempt.
    • ownagefool 13y ago
      He span for me, but only when we were on the last two bullets, which was about the same time I was spinning.
      • StavrosK 13y ago
        I always spun, and I'd say he spun around 50% of the time. We took around 10 turns, too.
  • tomjen3 13y ago
    Because it is cheating. The chance of the nth person getting the revolver (with no spin) is 1 - (n-1)/6, so the chance of the nth person dying is 1 - (n - 1) / 6 times the chance of a bullet in the chamber which is n/6. You spin and the last one becomes n/6, which means that the game is biased in favor of later starters.
    • StavrosK 13y ago
      Yeah, but then the sixth person has a 100% chance of dying, I wouldn't call that biased in their favor. It's fairer if everyone just always spins.
      • tomjen3 13y ago
        They have a 100% chance of dying if the gun gets to them which it will do only 1/6 of the time. Wherease if the sixth person spins, then they have a 1/6 chance of blowing their brains out and a 1/6 chance the gun gets to them, for a total of only 1/36 chance of no brain, compared to a 6/36 chance of no brain for the first guy, 5/36 for the second guy (5/6 chance that he has to pull the trigger, 1/6 chance he dies if he has to pull the trigger), third guy has 4/6 chance of having to pull the trigger for a combined 4/36 (which reduce to 1/9), fourth guy has a fifty-fifty whether he has to pull the guy which gives him combined 3/36 (which reduce to 1/12), fith guy has to pull the trigger only 2/6 which gives him a measly 2/36 (reduces to 1/18). That was the spinning case. In case there is no spin after the first pull of the trigger: first guy has 1/6 chance of shooting his brains out, which is the same as the last example. Second guy has 5/6 chance of having to shoot, and 1/5 chance of blowing his brains out if he has to fire, for a combined 1/6 (same as the first guy). Guy two has to fire 4/6 and has 1/4 chance of blowing of his head if he has to fire, giving a total of 1/6. The numbers work through all the numbers. While it is true that the last person is fucked if he has to shoot, there is also only 1/6 chance he has to shoot, so his odds are as good as the rest of them. The problem with having to spin the gun in between is that you break the dependent variable that increase the chance of the gun going of on each non-bang but keep the one that lowers the properbility of having to fire.
        • StavrosK 13y ago
          Hmm, you're right, thanks for the explanation. I was thinking of the iterated 2-person case, but I guess the logic is the same there (you can spin in the beginning of every round, of course).
• path411 13y ago
  Wow, 13 attempts each before the gun finally went off. I thought this game was just joking with me and wouldn't ever go off.