4 ms·
Click on the "I" and the "O"
- deleted 13y ago[deleted]
- josemarie04 13y agoIt looks to be...try 11011011 =)
- frogpelt 13y agoThis one only works for some people. I am not one of them.
- Skalman 13y agoThat doesn't work for me. OIOIOOII does, though - it leads to https://developers.google.com/events/io/experiment-eightbit https://developers.google.com/events/io/experiment-eightbit.
- derleth 13y agoIf you replaced the O with 0, why not replace the I with 1?
- deleted 13y ago[deleted]
- beobab 13y ago11011011 took me to https://developers.google.com/events/io/experiment-song https://developers.google.com/events/io/experiment-song And 10010000 took me to https://developers.google.com/events/io/experiment-bacon https://developers.google.com/events/io/experiment-bacon Time to see if I can find any more! :)
- alexlatchford 13y agoAlso OIIIIIII
- svag 13y agoI put OIIIIIII and I got the same but in ASCII art. https://developers.google.com/events/io/experiment-ascii https://developers.google.com/events/io/experiment-ascii
- hkolek 13y agoI got OOIOIOIO which leads to https://developers.google.com/events/io/experiment-space https://developers.google.com/events/io/experiment-space
- jimeh 13y agoIOOOIOOO gives you https://developers.google.com/events/io/experiment-synth https://developers.google.com/events/io/experiment-synth
- deleted 13y ago[deleted]
- dm2 13y agospace: 00101010 pong: 10000001 simone: 11010011 eightbit: 01010011 song: 11011011 synth: 10001000 ascii: 01111111 bowling: 01110101 rocket: 01000101 burger: 00111001 cat: 11100111 bacon: 10010000 This was done a while ago.
- mambodog 13y agoYou can also just read the code (the third parameter is the decimal representation of the 'password'): ww.mode.register("home", ww.mode.HomeMode, null); ww.mode.register("cat", ww.mode.CatMode, 231, 8); var isAndroid = navigator.userAgent.match(/Android/); isAndroid || ww.mode.register("space", ww.mode.SpaceMode, 42, 8); ww.mode.register("pong", ww.mode.PongMode, 129, 8); ww.mode.register("bacon", ww.mode.BaconMode, 144, 8); ww.mode.register("simone", ww.mode.SimoneMode, 211, 8); ww.mode.register("eightbit", ww.mode.EightBitMode, 83, 8); ww.util.getAudioContextConstructor() && (ww.mode.register("song", ww.mode.SongMode, 219, 8), ww.mode.register("synth", ww.mode.SynthMode, 136, 8)); ww.mode.register("ascii", ww.mode.AsciiMode, 127, 8); ww.mode.register("bowling", ww.mode.BowlingMode, 117, 8); ww.mode.register("rocket", ww.mode.RocketMode, 69, 8); ww.mode.register("burger", ww.mode.BurgerMode, 57, 8);
- dm2 13y agoSure, if you assume everyone has the amazing ability to do decimal to binary conversions in their head. Also assuming that everyone has the skill to dig through javascript files.
- nightpool 13y agocough https://www.google.com/#&q=231+in+base+2&oq=27+in+base+2 https://www.google.com/#&q=231+in+base+2&oq=27+in+ba... Or, you know, Windows Calculator? Or Gcalctool? Or, if you want overkill: http://www.wolframalpha.com/input/?i=231+in+base+2 http://www.wolframalpha.com/input/?i=231+in+base+2
- pygy_ 13y agoDecoding is easy with pen and paper, if not mentally. You must know your powers of two. In the order that concerns us: 128, 64, 32, 16, 8, 4, 2, 1 ---- Let's decompose 231. ---- 231 >= 128; That's a 1 in first position. 1 231 - 128 = 103 >= 64; We have a one in the second position. 11. 103 - 64 = 39 >= 32; One in the third position. 111. 39 - 32 = 7 < 16; Zero in the fourth position. 1110. 7 < 8; Zero in the fifth place. 11100 7 >= 4; 111001 7 - 4 = 3 >= 2; 1110011 3 - 2 = 1 >= 1; Final result: 11100111. Enjoy your cats :)
- mherdeg 13y agoSee http://stackoverflow.com/questions/15265562/what-are-all-of-the-google-i-o-2013-registration-easter-eggs http://stackoverflow.com/questions/15265562/what-are-all-of-... for more information.
- bcariveau 13y agoThis has been posted several times: https://news.ycombinator.com/item?id=5670648 https://news.ycombinator.com/item?id=5670648
- Luit 13y agoI see some just found the piece of JavaScript that registered the handlers, and others found lists by those people, but... did anyone else find the codes manually? I did. I quickly realised that it'd break off the code as soon as it couldn't lead to a match, greatly reducing the search space (which was only 256 options to begin with). As soon as I noticed that, I worked out all the codes by hand in only 15 minutes (including playing with the experiments I found). I just iterated through the search space (starting at all zeroes, counting up in binary) and eliminated whole sets of numbers as soon as it broke off the input. e.g. starting with all zeroes it breaks off at the third zero, meaning anything under 00100000 was impossible (immediately eliminating 32 of those 256 options in my search). Did anyone else do that too? Perhaps more interesting: did anyone have a completely different approach?
- Luit 13y agoAnd another question: what would this be called as a software algorithm? Is it a binary tree walk?
- moron4hire 13y agoYes, I did this as well. Was quite easy on my phone.
- kylesethgray 13y ago0111111 got me to an ASCII version of the logo