This is a good solution that I did not think of at the time. But it is no less expensive than the final (int)(f + 0.49999997f), to compare apples with apples (b

This is a good solution that I did not think of at the time. But it is no less expensive than the final (int)(f + 0.49999997f), to compare apples with apples (both still need to be guarded against overflow in the conversion).