3 ms·
Here's a 1 liner port in ruby : (l = ->(n,s=',o=0,c=0){ puts s and return if s.length == n || l.call(n,s+')',o,c+1) || o<n/2 && l.call(n,s+'(',o+1,c) if o>=c
by shadykiller 13y ago
Here's a 1 liner port in ruby :
(l = ->(n,s=',o=0,c=0){
puts s and return if s.length == n || l.call(n,s+')',o,c+1) || o<n/2 && l.call(n,s+'(',o+1,c) if o>=c
}).call(6)
- spicavigo 13y agoShame on you!