4 ms·
I can solve it with just 5 lines. You just have to get the pen to infinity and then come back. Wait, if infinity wraps around that'll take just one line!
by kaoD 14y ago
I can solve it with just 5 lines. You just have to get the pen to infinity and then come back.
Wait, if infinity wraps around that'll take just one line!
- eCa 14y agoWhat if you wrap the paper (if the dots are on paper) and draw a line round-and-round? A bit hard to ensure that it's straight though..
- kaoD 14y agoWho needs paper when you have ℝ²? :P
- bcoates 14y agoIt doesn't say you have to go through the center of the dot. If you angle them a bit 5 non-infinite lines will do.
- DrStalker 14y agoIt doesn't have to go to infinity. Look at this solution for 9 dots/three lines: http://www.goodmorningcreativity.com/wp-content/uploads/2010/10/9-dot-puzzle-3-lines-solution.jpg http://www.goodmorningcreativity.com/wp-content/uploads/2010... That scales up to whatever sized square of dots you like, provided the "dots" are not points but are circles with a non-zero diameter.
- yk 14y agoI am pretty sure that it is meant to be solved on a compact, simple connected subset of |R^2, with Euclidean metric.
- S4M 14y agoCareful with that. If the frontier of that subset is not far enough from the points, the problem will not be solvable.
- yk 14y agoAnd probably the word 'open' is also missing, then I can always find an embedding such that there is enough room :)
- kaoD 14y agoI'm pretty sure I was just joking.
- yk 14y agoNever meant to imply otherwise. But you are raising a good point, if one thinks about the general problem then it is not really straightforward to embed the points in |R^n instead of (for example) a torus.
- deleted 14y ago[deleted]