Interesting. Power in France costs ~$.03/kWh. So to boil a kilogram (i.e., a liter) of water (ignoring the heat of fusion) takes 100 J = .03 kWh which costs a

Interesting. Power in France costs ~$.03/kWh. So to boil a kilogram (i.e., a liter) of water (ignoring the heat of fusion) takes 100 J = .03 kWh which costs about $.001. Looks good to me. (I mean, those little water bottles sell for like $5/liter.)