4 ms·
In fact you just want: let numbers: ~[int] = ~[1,2,3]; When you allocate a vector on the heap, you don't need to specify the size.
by spicyj 14y ago
In fact you just want:
let numbers: ~[int] = ~[1,2,3];
When you allocate a vector on the heap, you don't need to specify the size.
- drbawb 14y agoI was thinking you might have a function that operates on some fixed length vector. For e.g: `fn foo(bar: ~[int, ..3]) { ... }`, and the compiler would enforce that you only pass vectors of length 3 to that function. But since I can't get `~[int, ..3] = ~[1,2,3]` (etc.) to compile that seems to be impossible w/ vectors on the heap?
- spicyj 14y agoI believe you can't do that. You can, however, make a function that only operates on 3-tuples: fn foo(bar: (int, int, int)) { ... }
- pcwalton 14y agoIt's a bug. Sorry about that. For now, write the type as `~([int, ..3])`.
- spicyj 14y agoI stand corrected -- thanks, didn't realize that you could have a pointer to a fixed-length vector.