7 ms·
Whoops, I did botch up the syntax on my listed example. I compiled release-0.6; and sure enough `let numbers: [int, ..3] = [1,2,3];` compiles. `let numbers: ~
by drbawb 14y ago
Whoops, I did botch up the syntax on my listed example.
I compiled release-0.6; and sure enough `let numbers: [int, ..3] = [1,2,3];` compiles.
`let numbers: ~[int, ..3] = ~[1,2,3];` does not compile on my system though. Ditto for the @ sigil.
(Expected `~[int * 3] but found ~[<VI2>]`)
My understanding is that the first example [from the docs] allocates the vector on the stack.
My uncompilable examples should be equivalent except that they use the heap for storage.
Is there a reason this shouldn't compile?
Thanks so much for the reply!
- spicyj 14y agoIn fact you just want: let numbers: ~[int] = ~[1,2,3]; When you allocate a vector on the heap, you don't need to specify the size.
- drbawb 14y agoI was thinking you might have a function that operates on some fixed length vector. For e.g: `fn foo(bar: ~[int, ..3]) { ... }`, and the compiler would enforce that you only pass vectors of length 3 to that function. But since I can't get `~[int, ..3] = ~[1,2,3]` (etc.) to compile that seems to be impossible w/ vectors on the heap?
- spicyj 14y agoI believe you can't do that. You can, however, make a function that only operates on 3-tuples: fn foo(bar: (int, int, int)) { ... }
- pcwalton 14y agoIt's a bug. Sorry about that. For now, write the type as `~([int, ..3])`.
- spicyj 14y agoI stand corrected -- thanks, didn't realize that you could have a pointer to a fixed-length vector.