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Though I agree, there are only a handful of Array.prototype methods, and I believe Underscore falls back to them when they are available. I imagine you could r
by bsimpson 14y ago
Though I agree, there are only a handful of Array.prototype methods, and I believe Underscore falls back to them when they are available. I imagine you could read fogus's work, then substitute where appropriate if you're already well-versed in JS. "I know I can use [].forEach instead of _.each."