4 ms·
You can override the .equals() for your subtype but look at the check: if (n.divide(root).equals(root)) { It never calls root.equals(). It calls .equals()
by raylu 14y ago
You can override the .equals() for your subtype but look at the check:
if (n.divide(root).equals(root)) {
It never calls root.equals(). It calls .equals() on the result of the .divide(), which is a standard java.math.BigInteger.