3 ms·
The only part of this that would be difficult is ensuring that there is no single dark pixel which is surrounded by all white pixels. As the dark pixel represen
by biot 14y ago
The only part of this that would be difficult is ensuring that there is no single dark pixel which is surrounded by all white pixels. As the dark pixel represents material and the white pixel is empty space, you'll need to use thin supporting structures within the QR margin of error otherwise there wouldn't be anything to hold the material in place. Do a Google Image search for "letter stencil" for what I mean by thin supporting structures.
That small caveat aside, it's super easy to construct: start with a solid block of material, take QR code 1, and from one face carve out the white pixels all the way through, keeping any thin connector pieces as required. Rotate to another face, do the same for QR code 2, rotate again, and do the last face for QR code 3. The remaining structure is what you 3D print.
- NickNameNick 14y ago>ensuring that there is no single dark pixel which is surrounded by all white pixels You mean, like the registration and alignment markers in three of the four corners?
- ctdonath 14y agoDid you even go to the link? First picture on the page obviously shows narrow diagonal connector pieces as required to support weak or unsupported components.
- biot 14y agoYou must have misread my comment. I stated that the connecting pieces are the only hard part in generating such a cube, not that connecting pieces weren't used in the cube shown. The next time you feel someone is in error, consider presenting your argument in a nicer tone. The use of "did you even" and "obviously" makes you seem like a dick.