2 ms·
Proof by contradiction is almost never necessary. Proof that if a number has a rational number square root, it must be a square: Let's suppose that sqrt(p
by trhtrsh 14y ago
Proof by contradiction is almost never necessary.
Proof that if a number has a rational number square root, it must be a square:
Let's suppose that sqrt(p) = a/b
That means that p = (a^2)/(b^2)
That means that p * b^2 = a^2
Therefore p is a square (by counting prime factors).