3 ms·
If you'd ever been to a Conway lecture you'd know that this is entirely par for the course for him.
by dfranke 18y ago
If you'd ever been to a Conway lecture you'd know that this is entirely par for the course for him.
- RiderOfGiraffes 18y agoKnowing Conway as I do, this is not only par for the course, it is actively to be expected. If there weren't comments like this then it would be a spoof. And there is no semantic confusion about "Free Will". The naming of the theorem is stated in those terms, but the work itself is independent of the precise meaning. That's why this is such an interesting result. The care taken to make it independent of the semantics attached to that term is, again, entirely to be expected, and makes the result compelling.