4 ms·
C++ is amazingly distracting. There's an algorithm in here, but it's hard to see through all the void fractal(window<int> &scr, window<double> &fract, int iter
by crawshaw 14y ago
C++ is amazingly distracting. There's an algorithm in here, but it's hard to see through all the
void fractal(window<int> &scr, window<double> &fract, int iter_max, std::vector<int> &colors, const std::function<std::complex<double(std::complex<double>, std::complex<double>)> &func, const char *fname, bool smooth_color);
- lclarkmichalek 14y agoDoes slightly seem like some typedefs might have helped. Particularly the `func` type signature.
- Jabbles 14y agoThat's unfair! The algorithm is in the function "escape", not the function "fractal". escape's function signature is much simpler: int escape(std::complex<double> c, int iter_max, const std::function<std::complex<double>(std::complex<double>, std::complex<double>)> &func) At least we get to use "auto" when we define func, though: auto func = [] (std::complex <double> z, std::complex<double> c) -> std::complex<double> {return z * z * z + c; };
- alpatters 14y agoYou could always let the compiler work it out for you. template< typename Func > int escape(std::complex<double> c, int iter_max, Func& func)