4 ms·
It's also not ideal because it's ratiometric to the supply voltage, not reference ground. They're reading the voltage across R2, and subtracting that from "5V"
by djahng 18y ago
It's also not ideal because it's ratiometric to the supply voltage, not reference ground. They're reading the voltage across R2, and subtracting that from "5V" to determine the voltage across the sensor.
There should also be an anti-aliasing filter.