3 ms·
Correction, what's important is that the skews from each clock are cancelled. Doing both measurements on one clock is a special case. For example, if you measu
by Strilanc 14y ago
Correction, what's important is that the skews from each clock are cancelled. Doing both measurements on one clock is a special case.
For example, if you measure the skewed time for A->D as (arrival time on D) - (send time on A) and then later measure the skewed time for A->B->C->D in the same way, you can get the non-skewed path difference by subtracting the two skewed times.
- niggler 14y agoThat's actually incorrect because of drift (if D's clock is faster than A's clock, if you don't correct for drift the measurements can't be reliably compared). You'd have to correct for drift for every step (A->B, B->C, C->D) before you start.
- Strilanc 14y agoRight, I was assuming negligible clock drift between when each measurement was performed.