3 ms·
I'd really like to know more. I've looked around and can't find anything. Can anyone link to the paper they published on this?
by EthanHeilman 14y ago
I'd really like to know more. I've looked around and can't find anything. Can anyone link to the paper they published on this?
- amper5and 14y agoAs I linked further down, this is probably based on Adi Shamir's (of RSA) threshold sharing scheme [1] [2]. Essentially, this approach splits any "secret" into n parts, requiring that k of them are necessary to reconstruct the original secret. It relies on the fact that k points are necessary to reconstruct a k-1 order polynomial. So if you hand out n points, with n > k, then any k of these points can be used to reconstruct the polynomial, whose y-intercept is the "secret". The coefficients of the polynomial are random. There are other [3] sharing schemes, and for the trivial k = n case, Shamir's scheme is probably overkill. [1] http://en.wikipedia.org/wiki/Shamir%27s_Secret_Sharing http://en.wikipedia.org/wiki/Shamir%27s_Secret_Sharing [2, PDF] http://citeseerx.ist.psu.edu/viewdoc/download?doi=10.1.1.80.8910&rep=rep1&type=pdf http://citeseerx.ist.psu.edu/viewdoc/download?doi=10.1.1.80.... [3] http://en.wikipedia.org/wiki/Secret_sharing http://en.wikipedia.org/wiki/Secret_sharing UPDATE: Here are some links to RSA's "Distributed Credential Protection" offering [4] and the white paper [5] describing it. [4] http://www.emc.com/security/rsa-distributed-credential-protection.htm http://www.emc.com/security/rsa-distributed-credential-prote... [5, PDF] http://www.emc.com/collateral/software/white-papers/h11013-rsa-dcp-0812-wp.pdf http://www.emc.com/collateral/software/white-papers/h11013-r...