3 ms·

Neither. But for the sake of argument, I'd rather see ['10','10','10','10'].map(Number);

• camus 14y ago
  ['10','10','10','10'].map(Number); this is one is correct ['10','10','10','10'].map(String); this one makes sense ['10','10','10','10'].map(Object); i'd like somebody to explain me this one ????????? Javascript is really difficult as soon as one try to do non trivial stuffs.
  • ricardobeat 14y ago
    Object('abc') is the same as new String('abc'), Object(1) the same as new Number(1) - it just calls the .constructor
    • iso-8859-1 14y ago
      but "new Number(x)" is not equal to "Number(x)". So, it's tricky, I guess?
      • ville 14y ago
        Number(x) performs a type conversion to number, new Number(x) constructs a primitive wrapper object Number: typeof Number("10") //=> "number" typeof new Number("10") //=> "object" The same applies to other wrapper objects, that is, Boolean and String.