4 ms·
http://i.imgur.com/kaOa0G3.gif http://i.imgur.com/kaOa0G3.gif Here's a version I found on reddit a while back.
by mepet 14y ago
http://i.imgur.com/kaOa0G3.gif http://i.imgur.com/kaOa0G3.gif
Here's a version I found on reddit a while back.
- vinhboy 14y agowhat exactly is that little dirt stain that moves from cylinder to cylinder supposed to be? is it supposed to represent tension or something?
- tptacek 14y agoIt's the currently binding cylinder. With the right amount of tension applied via the wrench, one pin binds at a time, which is what allows you to set the pins one at a time.
- TallboyOne 14y agoWhat's the difference in feeling where he's 'testing' which one's the binding cylinder or not? Is it just a tiny bit more 'grainy' harder to push or something?
- tptacek 14y agoThe binding pin won't bounce up and down when you actuate it with the pick. The non-binding pins won't offer any resistance at all. Also, when you manage to get the binding pin to the shear line, the tension wrench will sometimes give up a little more rotation.
- RandallBrown 14y agowhy does only one cylinder bind at a time? It seems to me like the lock shouldn't be able to turn at all until all of the cylinders are pressed to the right height.
- SquareWheel 14y agoDue to imperfections in the lock. It only takes a tiny difference for that tension to not be applied evenly so you can focus on one pin at a time.
- hoov 14y agoManufacturing tolerances aren't 100% perfect.
- jasonm23 14y agoit's the next 'key' pin. (the little stain is a key icon.)
- sev 14y agoInteresting. What is that little gold-ish looking thing that moves from one pin to the other in this gif?
- macalicious 14y agoIt's suppose to show you which pin is the correct one. The lock picker obviously can't know that's why he tries all of them.
- tadfisher 14y agoWhen you turn a lock, small machining defects mean that more load is borne by one pin than the others. Pushing up that pin while applying torque (using the allen wrench in the GIF) will cause that pin to be held up, which applies more load to some other pin.