3 ms·
I think they mean something like: c = make(chan bool) go doSomeWork(c) select { case b := <- c: # do something here if something happen
by ciniglio 14y ago
I think they mean something like:
c = make(chan bool)
go doSomeWork(c)
select {
case b := <- c:
# do something here if something happened on the channel
case <- time.After(5 * time.Second):
# timed out :-(
}
- RyanZAG 14y agoWell the timeout can be handled in java too Result result = future.get(5, TimeUnit.Second); if (result == null) // do something if timed out else // do something with result My original question was phrased badly though, and what I meant to ask was: is the underlying implementation faster? Since Golang is designed as a systems language, is the channel/gorouting system a lot more performant than the Executor/future method of Java? EDIT: I see what newobj is talking about now: With the Java method, the 'task queue' in this case is very rigid and would be hard to add futures from multiple locations, while the goroutine method allows easy access to add new messages to the channel from anywhere. You could probably emulate the goroutine method using a synchronized queue or similar, but the goroutine version handles it automatically.
- laureny 14y agoRight, just a nit pick:t if get() times out, it throws a TimeoutException instead of returning null (much cleaner).
- laureny 14y agoRight, just a nit pick:t if get() times out, it throws a TimeoutException instead of returning null (much cleaner).
- NateDad 14y agoFYI - you can also have 100,000 goroutines on a standard desktop without hitting resource problems (the go authors mentioned debugging a system in production that had 1.3 million). I doubt the same could be said for futures.