4 ms·
0 \in N, 5 \in N => (0/5) \in Q. Therefore 0 \in Q. QED.
by DIFF 14y ago
0 \in N, 5 \in N => (0/5) \in Q. Therefore 0 \in Q. QED.
- chris_wot 14y ago\in?
- bane 14y ago\in means "in the set of" Given the definition "The definition of a rational number is a number that can be expressed as the quotient of two integers where the denominator is not 0." Let N be the set of all integers and Q be the set of all rational numbers. Trivially 0 is in the set N, 5 is in the set N by the definition 0/5 is in Q. Therefore 0 is in Q. QED.
- deleted 14y ago[deleted]
- chris_wot 14y agoAh, I see! Deleted my old comment. Nice :-)
- v-yadli 14y agoWatch out for your proof. Q is constructed as a field with + and x only. The availability of the inverse operator is not well documented :-D