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Actually I've done the hash on this approach and this still results in a losing game for C. Instead of HH and TT being winners with this approach, HT and TH be
by mchannon 14y ago
Actually I've done the hash on this approach and this still results in a losing game for C.
Instead of HH and TT being winners with this approach, HT and TH become winners with this approach. Any combination of opposite or agreement will result in the same net odds.
The way for C to win is for A or B to treat it randomly.
A very interesting experiment would be to test how long it would take a random human subject A with no contact with a consistent B (but a memory for past results) to figure out how to win (in cases where they were told winning was possible, impossible, or neither).
- gmcrews 14y agoYes, but my point was that one team member uses HH & TT, while the other team member uses HT & TH. This is always a loss for the team regardless of how the flips turn out.