3 ms·
Don’t Lamport timestamps require all nodes to be known in advance? Powerful concept but impractical and far too unscalable to be used globally.
by BobbyTables2 1mo ago
Don’t Lamport timestamps require all nodes to be known in advance?
Powerful concept but impractical and far too unscalable to be used globally.
- gritzko 1mo agoLike IP addresses, right.
- yencabulator 1mo agoYou can manage version vectors with large random IDs: [(random_id, clock), ...]. That's not the problem. The problem is you can never remove a node from the clock (without losing properties). Most of the Xanadu data structure implementations, like ZigZag, just don't perform well enough at web scale.