3 ms·
I'm pretty sure that's incorrect. The whole point of the center of mass is that it's at the intersection of all the bisecting lines. If you slice a shape in two
by fluoridation 1mo ago
I'm pretty sure that's incorrect. The whole point of the center of mass is that it's at the intersection of all the bisecting lines. If you slice a shape in two and you don't get two parts of equal area then you didn't pass through the center of mass.
- gus_massa 1mo agoThe vertial bisection of this: XX XX XX|XXXXXXXXXX XX XX is the | symbol, but the center of mass is near the o in the next graphic. XX XX XXXXoXXXXXXXX XX XX
- fluoridation 1mo agoYou're just asserting that. Why would the center of mass be further to the right from the vertical bisection? That would make it so the left side has a mass of 12.5 versus 8.5 on the right. If you were to pivot that shape freely from that point, it wouldn't stay balanced, it would swing until it ends up as an upside-down T.
- gus_massa 1mo agoYou must consider how far away from the point they are in the horizontal direction. https://en.wikipedia.org/wiki/Center_of_mass#Definition https://en.wikipedia.org/wiki/Center_of_mass#Definition This is very unbalanced: 30 to the right and 55 to the left. 21 21 21|123456789A 21 21 This is almost balanced (my graphic is not perfect). 38 the right and 36 to the left. 43 43 4321o12345678 43 43
- fluoridation 1mo agoFair enough. I was thinking of center of mass as equivalent to the centroid and only taking into account geometric shape, not leverage.