3 ms·
Energy loss from air resistance typically is quadratic, not exponential, with regard to velocity. So it’s worth much less than you’re arguing. And the arm has t
by pletnes 1mo ago
Energy loss from air resistance typically is quadratic, not exponential, with regard to velocity. So it’s worth much less than you’re arguing. And the arm has to rotate from what I can understand, so the end rotational velocity - and hence, rotational energy - would be the same?
- getlawgdon 1mo agoIsn't drag either linear (proportional to velocity) or quadratic (proportional to velocity squared) depending on the scenario? But yes quadratic for things at this scale?
- stackghost 1mo agoDrag is linear with velocity under Stokes' Law which assumes laminar flow and a very very low Reynolds number, and does not apply to ballistic projectiles flying through air. Aerodynamic drag on the kinds of things that are involved in trebuchets is always quadratic with velocity.
- chocrates 1mo agoAny idea how adding a flywheel to the system would change it? Could we store more energy in the arm?