3 ms·

OK I cheated and used google and found (60 chars): for i in range(1,101):print'FizzBuzz'[ii%34:8--i**4%5]or i Pastebin of my explanation: http://pastebin.

by glomph 14y ago

OK I cheated and used google and found (60 chars): for i in range(1,101):print'FizzBuzz'[i*i%3*4:8--i**4%5]or i Pastebin of my explanation: http://pastebin.com/raw.php?i=00Db30FF http://pastebin.com/raw.php?i=00Db30FF EDIT: ugh, sometimes I hate markdown, moved post to pastebin.

GregBuchholz 14y ago
Awesomely ingenious use of math above. 59 if newlines count as 1. i=1 while i<101:print'FizzBuzz'[i*i%3*4:8--i**4%5]or i;i+=1
- twiceaday 14y ago
  Much simpler solution in 59 chars n=1 while n<101:print'Fizz'*(n%3<1)+'Buzz'*(n%5<1)or n;n+=1
- twiceaday 14y ago
  I came up with a shorter way to write the first index! n%-3&4 unbelievably it works
  - glomph 14y ago
    haha, clever!
glomph 14y ago
Should have been empty string f[4:4]