3 ms·
This is true for finite sets. For infinite sets, the Sierpinski triangle is a counterexample.
by scythe 2mo ago
This is true for finite sets. For infinite sets, the Sierpinski triangle is a counterexample.
- ky3 2mo ago> the Sierpinski triangle is a counterexample How so? It's bounded by the large initial triangle. The line containing any two of the vertices doesn't intersect any other point.
- tzs 2mo agoThat’s an uncountable set. If we want a counter example for uncountable sets a simpler example is a circular area. Anyone happen to know if it is true for countably infinite sets?
- namibj 2mo agoJust a regular grid? That's countable you just go in a spiral.