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Whether or not it’s on par famously or difficulty level doesn’t predict whether the others will fall. They’re unique problems and math isn’t linear - the Jacobi
by vlovich123 3mo ago
Whether or not it’s on par famously or difficulty level doesn’t predict whether the others will fall. They’re unique problems and math isn’t linear - the Jacobian it managed to find a counterexample and relied on other proofs that had been developed showing >3 case == 3 dimensional case. However, the Riemann may not fall in the same way because it may actually be true or the surrounding math isn’t quite ready to tackle that problem.
- GPerson 3mo agoWhen I was in grad school we talked about the Jacobian conjecture as something that would never be solved, and not really even worth thinking about since it’s impossible. There’s been a lot more big open problems solved by AI than which reach the front page of news websites like this. Based on all of these problems getting solved fast I’m just saying I’d be surprised if the Riemann hypothesis lasts another year.