3 ms·
that definition only converges for Re(z)>1. for Re(z)<=1, you need alternate formulas
by adgjlsfhk1 3mo ago
that definition only converges for Re(z)>1. for Re(z)<=1, you need alternate formulas
- seanhunter 3mo agoYes. Riemann gives them in the paper, including derivation, it’s just a bit annoying to type/read them here because hn doesn’t support mathjaxx. https://www.claymath.org/wp-content/uploads/2023/04/Wilkins-translation.pdf https://www.claymath.org/wp-content/uploads/2023/04/Wilkins-...
- zombot 3mo agoI'm just not mathematician enough to convert that into a C function. Let alone one that is both efficient and reasonably accurate.