4 ms·
No, it doesn't. It calls: void buffer_free(void *buf) { if (buf != null_buffer_singleton) free(buf); }
by kazinator 3mo ago
No, it doesn't. It calls:
void buffer_free(void *buf)
{
if (buf != null_buffer_singleton)
free(buf);
}
- Joker_vD 3mo ago...which treats it differently from non-empty buffers :) But frankly, having a 1-byte buffer, pointer to which can serve as a sentinel value à la NULL (but dereferenceable!), and which you can pass to free() without it being deallocated is indeed rather useful.