3 ms·
The imaginary part of the transform.
by frozenport 14y ago
The imaginary part of the transform.
- nphrk 14y agoThe article uses the magnitude of the coefficients, which is computed using both the real and the imaginary part.
- dbaupp 14y agoThe phase portion isn't actually just the imaginary part, it's just the piece of information lost when one goes from real+imag -> magnitude, i.e. it's the argument of the complex number.