3 ms·
Although the notation choice is tediously abstract (imo) the set of available scalars (and vector components) here is actually a relabeling of Q[e^i], the small
by OgsyedIE 4mo ago
Although the notation choice is tediously abstract (imo) the set of available scalars (and vector components) here is actually a relabeling of Q[e^i], the smallest field containing the rationals and e^i.
It was a fun three minute proof, if any of you are like me in enjoying this kind of thing.