4 ms·
I must be missing something. Aren’t ~50% of 64-bit integers the product of the number 2 and another 32-bit integer?
by cobbzilla 4mo ago
I must be missing something. Aren’t ~50% of 64-bit integers the product of the number 2 and another 32-bit integer?
- mplanchard 4mo agoI don’t think so, because that only gets you up to 2x2^32, which is nowhere near halfway to 2^64
- slazaro 4mo agoGoing from 32 bits to 64 bits doesn't double the range (that would be adding 1 bit), it squares the range.
- jlarocco 4mo agoNo. 50% of them are the product of 2 and a 63-bit integer.