3 ms·

What is **int[3][5]

• ori_b 5mo ago
  A syntax error. You need a variable name, not a type name, in the middle.
  • ori_b 5mo ago
    And if you want 'int **arr[a][b]', it's a value that when you say 'x = **arr[m][n]', will evaluate to an int and assign it to x. Postfix has higher precedence than prefix.
  • fusslo 5mo ago
    or a rejected PR
• thrance 5mo ago
  A pointer to a pointer to a pointer to a pointer of integers.
• kazinator 5mo ago
  In C declaration syntax, there is a "stem" called declaration specifiers consisting of specifiers and qualifiers. That's where int can appear. After that, there is a declarator. In some cases, multiple declarators separated by a comma, which share the same "stem". int a, b, *c; // one stem consisting of "int", three declarators. The * is declarator syntax for deriving a pointer type. It never appears such that a type specifier would come after it somewhere to the right. Some languages have extended the C declaration syntax such that the type derivators can be moved from the declarator part to the "stem". For instance, as an alternative to: int a[10]; you can write int[10] a; This is how we could get **int[3] as a declarator stem indicating an array of 3 pointers to pointers to int. But it's not in C.
• arcfour 5mo ago
  The work of the mythical four star programmer? https://wiki.c2.com/?ThreeStarProgrammer https://wiki.c2.com/?ThreeStarProgrammer