3 ms·

My new interview-screening question will be "solve fizzbuzz without using division or modulus". Because it's still so easy that you don't want to hire anyone w

• petethered 14y ago
  Simple Perl Code my $i; my $fizz = 3; my $buzz = 5; for ($i = 1; $i <= 100; $i++) { if ($i ne $fizz && $i ne $buzz) { print "$i\n"; next; } if ($i eq $fizz) { print "fizz"; $fizz += 3; } if ($i eq $buzz) { print "buzz"; $buzz += 5; } print "\n"; } Edit for formatting
  • ukoki 14y ago
    or in stupidly terse Ruby... f,b=3,5;(1..100).each{|i|s='';(s,f='Fizz',3)if(f-=1)==0;(s,b=s+'Buzz',5)if(b-=1)==0;puts(s==''?i:s)}