4 ms·

klein bottle molecule?

Nevermark 5mo ago
No, but that leaves open the construction of a Half-Klein! I suspect to acheive the 4D needed for construction without undesirable intersection, it will have to be implemented with a dynamic repeating 3D-Volume cycle, essentially rendering the 4D shape in time. Much like time crystals.
- vi_sextus_vi 5mo ago
  A (nontrivial) 4D STM is all they need. AIUI no new synthesis. But.. that's "just" rendering software "just" like https://en.wikipedia.org/wiki/4D_scanning_transmission_electron_microscopy https://en.wikipedia.org/wiki/4D_scanning_transmission_elect... (Not in the sense that "time" is involved but in the sense that what distinguishes 3D from 4D is almost only software . The same way you can see 4D "all at once" on your 2D screen,but 4tuples coords!= code) But then again IBM have claimed quantum software=quantum hardware (see above).. they might or might not understand what is or is not needed?
gus_massa 5mo ago
No, imagine a licorine candy https://www.google.com/search?q=licorice+candy&tbm=isch https://www.google.com/search?q=licorice+candy&tbm=isch but the cross section is a +. (It's easier if you get one that is not twisted. Something like https://www.sugarrushlane.com/products/filled-red-licorice-swedish-candy?srsltid=AfmBOopOhrX8c1uvrtQ4PD_ChEebZGHdJ-YMP2QemgHu4KwvcPVxXN9l https://www.sugarrushlane.com/products/filled-red-licorice-s... but with 4 instead of 5 parts. Also imagine each of the 4 parts has a different color. ) Now make a circle with it. If you don't twist it, you get an horizontal surface that looks like a thick border of a circle, and a vertical surface that looks like the round wall of a cylinder. If you twist half a turn, when you connect the extremes the top of the + in one extreme is glued to the bottom of the + in the other extreme. Something similar withe the left and right parts of the +. Now you have two overlapped copies of a Möbious strip, each perpendicular to the other. If you twist a quarter of a turn, when you connect the extremes the top of the + goes to the right, the right to the bottom, the bottom to the left an the left to the top. So you get only one "strip?"
- lupire 5mo ago
  Note that the colors are important. You need a discrete structure with N rotational segments and a turn of 1/M. Otherwise any rational turn size will have have multiple Mobius strips.

No, but that leaves open the construction of a Half-Klein! I suspect to acheive the 4D needed for construction without undesirable intersection, it will have to be implemented with a dynamic repeating 3D-Volume cycle, essentially rendering the 4D shape in time. Much like time crystals.

vi_sextus_vi 5mo ago
A (nontrivial) 4D STM is all they need. AIUI no new synthesis. But.. that's "just" rendering software "just" like https://en.wikipedia.org/wiki/4D_scanning_transmission_electron_microscopy https://en.wikipedia.org/wiki/4D_scanning_transmission_elect... (Not in the sense that "time" is involved but in the sense that what distinguishes 3D from 4D is almost only software . The same way you can see 4D "all at once" on your 2D screen,but 4tuples coords!= code) But then again IBM have claimed quantum software=quantum hardware (see above).. they might or might not understand what is or is not needed?

gus_massa 5mo ago

No, imagine a licorine candy https://www.google.com/search?q=licorice+candy&tbm=isch https://www.google.com/search?q=licorice+candy&tbm=isch but the cross section is a +. (It's easier if you get one that is not twisted. Something like https://www.sugarrushlane.com/products/filled-red-licorice-swedish-candy?srsltid=AfmBOopOhrX8c1uvrtQ4PD_ChEebZGHdJ-YMP2QemgHu4KwvcPVxXN9l https://www.sugarrushlane.com/products/filled-red-licorice-s... but with 4 instead of 5 parts. Also imagine each of the 4 parts has a different color. ) Now make a circle with it. If you don't twist it, you get an horizontal surface that looks like a thick border of a circle, and a vertical surface that looks like the round wall of a cylinder. If you twist half a turn, when you connect the extremes the top of the + in one extreme is glued to the bottom of the + in the other extreme. Something similar withe the left and right parts of the +. Now you have two overlapped copies of a Möbious strip, each perpendicular to the other. If you twist a quarter of a turn, when you connect the extremes the top of the + goes to the right, the right to the bottom, the bottom to the left an the left to the top. So you get only one "strip?"

lupire 5mo ago
Note that the colors are important. You need a discrete structure with N rotational segments and a turn of 1/M. Otherwise any rational turn size will have have multiple Mobius strips.