5 ms·
Not necessarily. You'd be correct given hidden variables. But we know pretty convincingly that quantum anything does not have hidden variables. https://en.wi
by fooker 6mo ago
Not necessarily.
You'd be correct given hidden variables.
But we know pretty convincingly that quantum anything does not have hidden variables.
https://en.wikipedia.org/wiki/Bell%27s_theorem https://en.wikipedia.org/wiki/Bell%27s_theorem
- messe 6mo agoIt doesn't have local hidden variables. That's an important distinction. I'm not sure a non-local hidden variable explanation of QM is any distinct from superdeterminism though.