3 ms·
An easier solution is to give each item a number of implied mediocre ratings (say 10 3s) to start. 1 rating, 5.0 = 35/11 = 3.18; 90 ratings, 4.5 = 435/100 = 4
by time_management 18y ago
An easier solution is to give each item a number of implied mediocre ratings (say 10 3s) to start.
1 rating, 5.0 = 35/11 = 3.18;
90 ratings, 4.5 = 435/100 = 4.35
The downside is that, since items with few ratings get mediocre scores, if there isn't a way for them to be visible, they won't get out of that rut. So a better approach might be to feature (on a "top 10" list) seven high scorers and 3 "rising stars" selected purely on average score.