3 ms·
It does, probabilistically. For any given customer C, the expected value EV(C) is... not much. By starting an opt-out process, a customer Co is revealed to have
by TeMPOraL 7mo ago
It does, probabilistically. For any given customer C, the expected value EV(C) is... not much. By starting an opt-out process, a customer Co is revealed to have EV(Co) = 0, which is less than not much.
- eru 7mo agoThough it's making the other customers statistically more valuable.