4 ms·

I would imagine since they are not circling the earth, that there will be pull of gravity and the camera would start to move relative to the spacecraft. But may

I would imagine since they are not circling the earth, that there will be pull of gravity and the camera would start to move relative to the spacecraft. But may not fast enough for a short exposure

dotancohen 6mo ago
The gravity of the Earth (and moon, and everything else) is uniform (i.e. no gradient) on the scale of things the size of that capsule at the distance that capsule is from them, on the order of time of the exposure of that photograph. So the gravity (from any source) will pull on the spacecraft and on the camera in the same fashion. To fully answer the question, the moon's gravitational gradient does pull on the Earth, the ocean closest to the moon, and the ocean furthest from the moon differently. But those are objects separated by thousands of kilometers, having hours of gravitational influence acting upon them.
gus_massa 6mo ago
Once you are out of the atmosphere and turn off your thrusters, you are on "fee fall" and the gravity on the camera, you and the spaceship produce the same acceleration and they cancel and it looks exactly like "zero gravity". It doesn't matter if you are in orbit around the Earth, going to the Moon.
- echoangle 6mo ago
  Actually not quite correct. The camera and spaceship will generally have different starting positions of their center of gravity but the same starting velocity, leading them to drift apart. The only real relevant thing for the photograph is rotation though as long as the camera doesn’t float in front of the window frame, and airflow is probably much more relevant for both points than gravity.
  - gus_massa 6mo ago
    > will generally have different starting positions of their center of gravity but the same starting velocity That are the tidal forces, they are quite small for a system of the size of Orion.
    - echoangle 6mo ago
      Right, I was talking technically. That’s what I tried to say in the second paragraph.
mr_toad 6mo ago
They’re not circling the Earth, but they’re still orbiting it. Their orbit is highly eccentric, and will be near the Moon at apogee.
- narmiouh 6mo ago
  Yeah, makes sense. I was assuming the vehicle was also deliberately accelerating which would make a difference on a floating camera, but if it isn't, then gravity is the only force and no relative difference.

I would imagine since they are not circling the earth, that there will be pull of gravity and the camera would start to move relative to the spacecraft. But may not fast enough for a short exposure

dotancohen 6mo ago

The gravity of the Earth (and moon, and everything else) is uniform (i.e. no gradient) on the scale of things the size of that capsule at the distance that capsule is from them, on the order of time of the exposure of that photograph. So the gravity (from any source) will pull on the spacecraft and on the camera in the same fashion. To fully answer the question, the moon's gravitational gradient does pull on the Earth, the ocean closest to the moon, and the ocean furthest from the moon differently. But those are objects separated by thousands of kilometers, having hours of gravitational influence acting upon them.

gus_massa 6mo ago

Once you are out of the atmosphere and turn off your thrusters, you are on "fee fall" and the gravity on the camera, you and the spaceship produce the same acceleration and they cancel and it looks exactly like "zero gravity". It doesn't matter if you are in orbit around the Earth, going to the Moon.

echoangle 6mo ago
Actually not quite correct. The camera and spaceship will generally have different starting positions of their center of gravity but the same starting velocity, leading them to drift apart. The only real relevant thing for the photograph is rotation though as long as the camera doesn’t float in front of the window frame, and airflow is probably much more relevant for both points than gravity.
- gus_massa 6mo ago
  > will generally have different starting positions of their center of gravity but the same starting velocity That are the tidal forces, they are quite small for a system of the size of Orion.
  - echoangle 6mo ago
    Right, I was talking technically. That’s what I tried to say in the second paragraph.

mr_toad 6mo ago

They’re not circling the Earth, but they’re still orbiting it. Their orbit is highly eccentric, and will be near the Moon at apogee.

narmiouh 6mo ago
Yeah, makes sense. I was assuming the vehicle was also deliberately accelerating which would make a difference on a floating camera, but if it isn't, then gravity is the only force and no relative difference.