4 ms·
This is a fantastic explanation. Thank you. The only part I am not following is how it is guaranteed that 1 bit is sufficient for the error value. Is this somet
by thrtythreeforty 6mo ago
This is a fantastic explanation. Thank you. The only part I am not following is how it is guaranteed that 1 bit is sufficient for the error value. Is this something the Lloyd-Max algorithm is responsible for ensuring? (Seems to me that if your quantization algorithm is crappy enough, you could need a large number of bits to store the error.)