2 ms·

so there's an unconditionally correct answer (it's also equal to abs(x) for x>0), and then there is an answer that is only correct for half the domain, which re

by exe34 7mo ago

so there's an unconditionally correct answer (it's also equal to abs(x) for x>0), and then there is an answer that is only correct for half the domain, which requires an additional assumption.

crubier 7mo ago
sqrt(square(i)) != abs(i) So no, it’s not unconditionally correct either.