3 ms·
Thanks, but where do they say that? I can only find this instance of "different" (as in "differentiable") in their article: Because the execution trace is part
by YeGoblynQueenne 8mo ago
Thanks, but where do they say that? I can only find this instance of "different" (as in "differentiable") in their article:
Because the execution trace is part of the forward pass, the whole process remains differentiable: we can even propagate gradients through the computation itself. That makes this fundamentally different from an external tool. It becomes a trainable computational substrate that can be integrated directly into a larger model.
- D-Machine 7mo agoIn the section "Programs into weights & training beyond gradient descent", near the end, they say: [...] *the compilation machinery we built for generating those weights** can go further. In principle, arbitrary programs can be compiled directly into the transformer weights, bypassing the need to represent them as token sequences at all. [...] [my emphasis] In the same section, they also continue: Weights become a deployment target: instead of learning software-like behavior, models contain compiled program logic. If logic can be compiled into weights, then gradient descent is no longer the only way to modify a model. Weight compilation provides another route for inserting structure, algorithms, and guarantees directly into a network. So they (almost-invisibly) admit they compile in the weights, but make it clearer this was the whole intention the whole time in later sentences.