3 ms·

> even if aarch64 is more memory efficient, it can’t be too drastic Why not? All the other advantages of M processors (performance, battery life) have absolute

• josephg 7mo ago
  Yeah. Also the bandwidth of modern soldered-on Mac SSDs is insane compared to where it was in the Intel era. The performance impact of moving applications in and out of swap should be much lower than it was a few years ago.
  • drdaeman 7mo ago
    That’s a fair point, I totally missed this factor, mostly thinking about binary sizes. You’re right, it would be different because of this.
  • AnthonyMouse 7mo ago
    > Also the bandwidth of modern soldered-on Mac SSDs is insane compared to where it was in the Intel era. This is because they're newer, not because they're soldered. PCIe 5.0 NVMe drives can do ~15GB/s without being soldered.
• drdaeman 7mo ago
  Because look around - same code compiled for x86_64 and aarch64 is not that drastically different in size, save for some special cases (like NumPy). Data structures are going to have even less differences. Then, assets are the same. I’ve cursorily checked few programs and difference seemed to about 10-20% (with some exceptions), so 8GiB RAM on an aarch64 is like 10GB on x86_64. Significantly nicer, not a life-changing nicer - you’re still very limited. Edit: Next comment has a very good point about memory and SSD bandwidth increases, allowing faster swap and compressed RAM performance. That’s something I haven’t considered. So maybe it’ll feel closer to a 16GiB old machine or something like that…