500 gal diesel = 1622 kg 17 stories = 46 meters Energy required = 1621 * 46 * g = 732 kJ Integrating PV=nRT, W = -nRT*ln(V₂/V₁) assume you're going to compr

500 gal diesel = 1622 kg 17 stories = 46 meters Energy required = 1621 * 46 * g = 732 kJ Integrating PV=nRT, W = -nRT*ln(V₂/V₁) assume you're going to compress the air to 150 psi, or 10 atm, so V₂/V₁ = 10. Assume T=10 degrees C. Solving for n, you need 880 moles of air. Putting this back through PV=nRT, we get a modest 190 gallons of air (compressed). So you need a 200 gallon tank with 150 psi storage. Look, here's one on craigslist for $400. http://eugene.craigslist.org/gms/3306858286.html http://eugene.craigslist.org/gms/3306858286.html